Integrand size = 35, antiderivative size = 152 \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\frac {2 (b d-a e)^2 (d+e x)^{3/2} \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^3 (a+b x)}-\frac {4 b (b d-a e) (d+e x)^{5/2} \sqrt {a^2+2 a b x+b^2 x^2}}{5 e^3 (a+b x)}+\frac {2 b^2 (d+e x)^{7/2} \sqrt {a^2+2 a b x+b^2 x^2}}{7 e^3 (a+b x)} \]
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Time = 0.05 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.086, Rules used = {784, 21, 45} \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\frac {2 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (d+e x)^{7/2}}{7 e^3 (a+b x)}-\frac {4 b \sqrt {a^2+2 a b x+b^2 x^2} (d+e x)^{5/2} (b d-a e)}{5 e^3 (a+b x)}+\frac {2 \sqrt {a^2+2 a b x+b^2 x^2} (d+e x)^{3/2} (b d-a e)^2}{3 e^3 (a+b x)} \]
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Rule 21
Rule 45
Rule 784
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int (a+b x) \left (a b+b^2 x\right ) \sqrt {d+e x} \, dx}{a b+b^2 x} \\ & = \frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int (a+b x)^2 \sqrt {d+e x} \, dx}{a b+b^2 x} \\ & = \frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \left (\frac {(-b d+a e)^2 \sqrt {d+e x}}{e^2}-\frac {2 b (b d-a e) (d+e x)^{3/2}}{e^2}+\frac {b^2 (d+e x)^{5/2}}{e^2}\right ) \, dx}{a b+b^2 x} \\ & = \frac {2 (b d-a e)^2 (d+e x)^{3/2} \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^3 (a+b x)}-\frac {4 b (b d-a e) (d+e x)^{5/2} \sqrt {a^2+2 a b x+b^2 x^2}}{5 e^3 (a+b x)}+\frac {2 b^2 (d+e x)^{7/2} \sqrt {a^2+2 a b x+b^2 x^2}}{7 e^3 (a+b x)} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.52 \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\frac {2 \sqrt {(a+b x)^2} (d+e x)^{3/2} \left (35 a^2 e^2+14 a b e (-2 d+3 e x)+b^2 \left (8 d^2-12 d e x+15 e^2 x^2\right )\right )}{105 e^3 (a+b x)} \]
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Result contains higher order function than in optimal. Order 9 vs. order 2.
Time = 0.25 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.45
method | result | size |
default | \(\frac {2 \,\operatorname {csgn}\left (b x +a \right ) \left (e x +d \right )^{\frac {3}{2}} \left (15 b^{2} e^{2} x^{2}+42 a b \,e^{2} x -12 b^{2} d e x +35 e^{2} a^{2}-28 a b d e +8 b^{2} d^{2}\right )}{105 e^{3}}\) | \(69\) |
gosper | \(\frac {2 \left (e x +d \right )^{\frac {3}{2}} \left (15 b^{2} e^{2} x^{2}+42 a b \,e^{2} x -12 b^{2} d e x +35 e^{2} a^{2}-28 a b d e +8 b^{2} d^{2}\right ) \sqrt {\left (b x +a \right )^{2}}}{105 e^{3} \left (b x +a \right )}\) | \(79\) |
risch | \(\frac {2 \sqrt {\left (b x +a \right )^{2}}\, \left (15 b^{2} x^{3} e^{3}+42 a b \,e^{3} x^{2}+3 b^{2} d \,e^{2} x^{2}+35 a^{2} e^{3} x +14 a b d \,e^{2} x -4 b^{2} d^{2} e x +35 a^{2} d \,e^{2}-28 a b \,d^{2} e +8 b^{2} d^{3}\right ) \sqrt {e x +d}}{105 \left (b x +a \right ) e^{3}}\) | \(116\) |
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Time = 0.30 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.65 \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\frac {2 \, {\left (15 \, b^{2} e^{3} x^{3} + 8 \, b^{2} d^{3} - 28 \, a b d^{2} e + 35 \, a^{2} d e^{2} + 3 \, {\left (b^{2} d e^{2} + 14 \, a b e^{3}\right )} x^{2} - {\left (4 \, b^{2} d^{2} e - 14 \, a b d e^{2} - 35 \, a^{2} e^{3}\right )} x\right )} \sqrt {e x + d}}{105 \, e^{3}} \]
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\[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\int \left (a + b x\right ) \sqrt {d + e x} \sqrt {\left (a + b x\right )^{2}}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.79 \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\frac {2 \, {\left (3 \, b e^{2} x^{2} - 2 \, b d^{2} + 5 \, a d e + {\left (b d e + 5 \, a e^{2}\right )} x\right )} \sqrt {e x + d} a}{15 \, e^{2}} + \frac {2 \, {\left (15 \, b e^{3} x^{3} + 8 \, b d^{3} - 14 \, a d^{2} e + 3 \, {\left (b d e^{2} + 7 \, a e^{3}\right )} x^{2} - {\left (4 \, b d^{2} e - 7 \, a d e^{2}\right )} x\right )} \sqrt {e x + d} b}{105 \, e^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 236 vs. \(2 (107) = 214\).
Time = 0.26 (sec) , antiderivative size = 236, normalized size of antiderivative = 1.55 \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\frac {2 \, {\left (105 \, \sqrt {e x + d} a^{2} d \mathrm {sgn}\left (b x + a\right ) + 35 \, {\left ({\left (e x + d\right )}^{\frac {3}{2}} - 3 \, \sqrt {e x + d} d\right )} a^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {70 \, {\left ({\left (e x + d\right )}^{\frac {3}{2}} - 3 \, \sqrt {e x + d} d\right )} a b d \mathrm {sgn}\left (b x + a\right )}{e} + \frac {7 \, {\left (3 \, {\left (e x + d\right )}^{\frac {5}{2}} - 10 \, {\left (e x + d\right )}^{\frac {3}{2}} d + 15 \, \sqrt {e x + d} d^{2}\right )} b^{2} d \mathrm {sgn}\left (b x + a\right )}{e^{2}} + \frac {14 \, {\left (3 \, {\left (e x + d\right )}^{\frac {5}{2}} - 10 \, {\left (e x + d\right )}^{\frac {3}{2}} d + 15 \, \sqrt {e x + d} d^{2}\right )} a b \mathrm {sgn}\left (b x + a\right )}{e} + \frac {3 \, {\left (5 \, {\left (e x + d\right )}^{\frac {7}{2}} - 21 \, {\left (e x + d\right )}^{\frac {5}{2}} d + 35 \, {\left (e x + d\right )}^{\frac {3}{2}} d^{2} - 35 \, \sqrt {e x + d} d^{3}\right )} b^{2} \mathrm {sgn}\left (b x + a\right )}{e^{2}}\right )}}{105 \, e} \]
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Timed out. \[ \int (a+b x) \sqrt {d+e x} \sqrt {a^2+2 a b x+b^2 x^2} \, dx=\int \sqrt {{\left (a+b\,x\right )}^2}\,\left (a+b\,x\right )\,\sqrt {d+e\,x} \,d x \]
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